2x^2+3x+8=3x-10

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Solution for 2x^2+3x+8=3x-10 equation:


Simplifying
2x2 + 3x + 8 = 3x + -10

Reorder the terms:
8 + 3x + 2x2 = 3x + -10

Reorder the terms:
8 + 3x + 2x2 = -10 + 3x

Add '-3x' to each side of the equation.
8 + 3x + -3x + 2x2 = -10 + 3x + -3x

Combine like terms: 3x + -3x = 0
8 + 0 + 2x2 = -10 + 3x + -3x
8 + 2x2 = -10 + 3x + -3x

Combine like terms: 3x + -3x = 0
8 + 2x2 = -10 + 0
8 + 2x2 = -10

Solving
8 + 2x2 = -10

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-8' to each side of the equation.
8 + -8 + 2x2 = -10 + -8

Combine like terms: 8 + -8 = 0
0 + 2x2 = -10 + -8
2x2 = -10 + -8

Combine like terms: -10 + -8 = -18
2x2 = -18

Divide each side by '2'.
x2 = -9

Simplifying
x2 = -9

Reorder the terms:
9 + x2 = -9 + 9

Combine like terms: -9 + 9 = 0
9 + x2 = 0

The solution to this equation could not be determined.

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